x^2+2x-3=x^2+3x-8

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Solution for x^2+2x-3=x^2+3x-8 equation: 



x^2+2x-3=x^2+3x-8

We move all terms to the left:

x^2+2x-3-(x^2+3x-8)=0

We get rid of parentheses

x^2-x^2+2x-3x+8-3=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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